2. Panen tidak berhasil.
3. Jika 2 x 2 = 4 maka 20 bilangan genap.
4. ${{r}^{2}}={{x}^{2}}+{{y}^{2}}$
$[{{r}^{2}}=-{{1}^{2}}+{{\left( \sqrt{3} \right)}^{2}}$
${{r}^{2}}=1+3$
$r=\sqrt{4}=2$
$alpha {}^\circ =Arc\tan \frac{\sqrt{3}}{-1}$
$=Arc\tan -\sqrt{3}$
$=-60{}^\circ $
$\left( 2,-60{}^\circ \right)$
5. $[x=r\cos \alpha {}^\circ $
$x=4\cos 30{}^\circ $
$x=4.\frac{1}{2}\sqrt{3}$
$x=2\sqrt{3}$
$y=r\sin \alpha {}^\circ $
$y=4\sin 30{}^\circ $
$y=2\left( \frac{1}{2} \right)$
$y=1$
$\left( 2\sqrt{3},1 \right)$
6. $\sin \left( a+b \right)=\sin a.\cos b+\cos a.\sin b$
$\sin 75=\sin \left( 30+45 \right)$
$=\sin 30.\cos 45+\sin 30.\cos 45$
$=\frac{1}{2}.\frac{1}{2}\sqrt{2}+\frac{1}{2}\sqrt{3}.\frac{1}{2}\sqrt{2}$
$=\frac{1}{4}\sqrt{2}+\frac{1}{4}\sqrt{6}$
$=\frac{1}{4}\left( \sqrt{2}+\sqrt{6} \right)$
7. $\cos \left( {{45}^{\circ }}+{{60}^{\circ }} \right)=\cos {{45}^{\circ }}+\cos {{60}^{\circ }}$
$=\frac{1}{2}\sqrt{2}+\frac{1}{2}$
$=\frac{1}{2}\sqrt{2}$
8. \[\frac{5}{120}=\frac{1}{2}\]
9. Dadu : $5=4$ Kemungkinan : $=36$
Dadu : $8=\frac{5}{9}$ Peluang : $\frac{9}{36}=\frac{1}{4}$
10. Me = $[Tb\frac{\left( \frac{n}{2}-Fk \right)}{Fme}.I$
= $52,5+\frac{1}{1+3}.3$
= $52,5+\frac{1}{4}.3$
= $52,5+\frac{3}{4}=60$
Q1 = ....
Letak = $\frac{20}{4}=5$
FQ = $5$
TB = $52,5$
FK = $4$
I = $3$
Q1 = $52,5+\frac{5-4}{5}.3$
= $52,5+\frac{1}{5}.3$
= $52,5+0,2.3$
= $52,5+6,6$
= $53,1$
Q3 = ….
Letak = $\frac{20.3}{4}=15$
FQ = $6$
TB = $61,5$
FK = $14$
I = $3$
Q1 = $61,5+\frac{15-4}{6}.3$
= $61,5+\frac{1}{6}.3$
= $61,5+0,5$
= $62$
Mean = $\frac{\sum\limits_{{}}^{{}}{F1.X1}}{\sum\limits_{{}}^{{}}{F1}}$
= $\frac{1143}{20}$
= $57,15$
11. $\int{\left( {{x}^{2}}+3x-2x-6 \right)dx}$
= $\frac{1}{3}{{x}^{3}}+\frac{1}{2}{{x}^{2}}-6x$
12. = ${{x}^{2}}-3x\int\limits_{1}^{2}{{}}$
= $\left( {{2}^{2}}-3.2 \right)-\left( {{1}^{2}}-3.1 \right)$
= $\left( 4-6 \right)-\left( 1-3 \right)$
= $-2-2=0$
13. y = $9-{{x}^{2}}$
$\int\limits_{-1}^{1}{\left( {{x}^{3}} \right)}dx=\frac{1}{4}.{{x}^{4}}$
= $\frac{1}{4}{{.1}^{4}}-\frac{1}{4}-{{1}^{4}}$
= $\frac{1}{4}--\frac{1}{4}$
= $\frac{1}{2}$ satuan
